An army contigent of 616 mmbers is to march behind an army band of 32 members in a parade. The 2 groups are to march in the same number of columns. Waht is the maximum number of columns in which they can march
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Maximum number of collums are the Hcf of 616 and 32
By applying Euclod's division lemma, a = bq+r
616 = 32×19+8
32 = 8×4+0
HCF of 616 and 32 is 8. Maximum number of collums in which they can march is 8
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