Math, asked by santoshyadav19061976, 11 months ago

an army contingent 616 members is to March behind an army of 32 members in parades. the two groups










Answers

Answered by moulee007
13

Answer:

8 groups can be marched.

Attachments:
Answered by Anonymous
41

 \huge{ \rm{ \color{cyan}{ \overline{ \underline{ |answer| }}}}}

 \boxed{ \bold{given :  - }}

  • Number of army contingent members=616
  • Number of army band members=32

 \boxed{ \bold{to \: find :  - }}

  • Maximum number of columns in which they can march.

 \boxed{ \bold{solution :  - }}

If the two groups have to march in the same column, we have to find out the Highest Common Factor between the two groups. [i.e., H.C.F. of 616 and 32]

By using Euclid's division algorithm to find the H.C.F., we get,

Since 616 > 32,

\: 616 = 32 \times 19 + 8

32= 8 \times 4 + 0

 \therefore  \rm\: h.c.f. \: of \: 616 \: and \: 32 = 8

Hence, The number of columns in which they can march is,

 \huge{ \bold{8 \: columns}}

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