Math, asked by santoshyadav19061976, 9 months ago

an army contingent 616 members is to March behind an army of 32 members in parades. the two groups










Answers

Answered by moulee007
13

Answer:

8 groups can be marched.

Attachments:
Answered by Anonymous
41

 \huge{ \rm{ \color{cyan}{ \overline{ \underline{ |answer| }}}}}

 \boxed{ \bold{given :  - }}

  • Number of army contingent members=616
  • Number of army band members=32

 \boxed{ \bold{to \: find :  - }}

  • Maximum number of columns in which they can march.

 \boxed{ \bold{solution :  - }}

If the two groups have to march in the same column, we have to find out the Highest Common Factor between the two groups. [i.e., H.C.F. of 616 and 32]

By using Euclid's division algorithm to find the H.C.F., we get,

Since 616 > 32,

\: 616 = 32 \times 19 + 8

32= 8 \times 4 + 0

 \therefore  \rm\: h.c.f. \: of \: 616 \: and \: 32 = 8

Hence, The number of columns in which they can march is,

 \huge{ \bold{8 \: columns}}

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