Question

an army contingent are 616 members is behind an army band of 32 members in a parade. the two groups are to March in the same number or columns,what is the maximum number of columns in which they can March?​

Answer 1

the HCF of 616 and 32 is 8. Therefore, 8 is the maximum number of columns in which they can march.

Step-by-step explanation:

you have to find first hcf

Answer 2

$\huge \fbox \red{Solution:}$

It is given that an army contingent of 616 members is to march behind an army band of 32

members in a parade. Also, the two groups are to march in the same number of columns.

Thus, we need to find the maximum number of columns in which they can march.

This is done by simply finding the HCF of the given two numbers.

Therefore, the maximum number of columns = H.C.F of 616 and 32.

$\fbox \blue{By applying Euclid’s division lemma}$

616 = 32 x 19 + 8

32 = 8 x 4 + 0.

So, H.C.F. = 8

$\fbox \blue{∴ The maximum number of columns in which they can march is 8.}$

$\bold\orange{Thanks}$