An army contingent of 1000 member is to March behind an army band of 56 member in a parade the two group are too much in a number of number of column what is the maximum number of column in which day can March
Answers
Answered by
9
HCF(1000,56) will give the maximum number of coloums in which they can march
To find HCF,we can use Euclid's algorithm
i.e-
1000=56×17+48
56=48×1+8
48=8×6+0
Therefore-the HCF(1000,56) is 8
So the maximum number of coloums in which they can march =8
To find HCF,we can use Euclid's algorithm
i.e-
1000=56×17+48
56=48×1+8
48=8×6+0
Therefore-the HCF(1000,56) is 8
So the maximum number of coloums in which they can march =8
Similar questions