an army contingent of 455 members is to march behind an army band of 42 members in a parade. the two groups have to march in the same number of columns.What is the maximum number of columns in they can march?
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Answered by
10
Given that,
Total no of army contingent = 455
No of members in a parade = 42
To find,
The maximum number of columns in they can march.
Solution,
It is mentioned that the two groups have to march in the same number of columns. To find the maximum no of column in they can march, we need to find the HCF of 455 and 42.
Prime factorization of 455: 5 x 7 x 13
Prime factorization of 42: 2 x 3 x 7
HCF (highest common factor) = 7
Hence, there are 7 no of column in they can march.
Answered by
7
The maximum number of columns in they can march
Step-by-step explanation:
- Total army continent = 455
- Parade members are = 42
- First of all we have to take the HCF of 455 and 42 to find out the columns.
- Factors of 455 is 5*7*13
- Factors of 42 is 2*3*7
- The highest and common factor in both HCF is 7
- So that here the maximum number of columns are 7 that they can march.
Learn more: Column, HCF
brainly.in/question/15332838
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