Math, asked by radhikanegi2006, 1 month ago

An army contingent of 612 members behind an army band of 23 members in a parade .The two groups are to march in the same no.of columns what is maximum no.of columns which they can march?

Answers

Answered by sanvi7031
16

There is a Mistake in the question :-

The Correct question will be -

An army contingent of 612 members behind an army band of 32 members in a parade .The two groups are to march in the same no.of columns what is maximum no.of columns which they can march?

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The maximum number of columns in which they can March is equal to the HCF of 32 & 616.

32 = 2×2×2×2

616 = 2×2×2×7×11

Hence, Highest common factor (HCF) of 32 & 616 = 2×2×2 = 8

\therefore Maximum number of columns in which they can March is 8.

Answered by itsmissloffer01
8

Answer:

There is a Mistake in the question :-

The Correct question will be -

An army contingent of 612 members behind an army band of 32 members in a parade .The two groups are to march in the same no.of columns what is maximum no.of columns which they can march?

\huge\red{\underbrace{\textsf{\textbf{\purple{Answer:-}}}}}

Answer:-

The maximum number of columns in which they can March is equal to the HCF of 32 & 616.

32 = 2×2×2×2

616 = 2×2×2×7×11

Hence, Highest common factor (HCF) of 32 & 616 = 2×2×2 = 8

\therefore∴ Maximum number of columns in which they can March is 8.

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