Math, asked by jashanp590, 7 months ago

An army contingent of 616 members is to march behind an army band of 32 members in
a parade. The two groups are to march in the same number of columns. What is the
maximum number of columns in which they can march?​

Answers

Answered by Anonymous
3

Answer:

The Continental Army was formed by the Second Continental Congress after the outbreak of the American Revolutionary War by the former British colonies that later became the United States of America. Wikipedia

Opponent(s): British government, British Army, Hessian mercenaries

Founder: Second Continental Congress

Founded: 14 June 1775

Answered by Anonymous
3

Answer....

HCF (616,32) is the maximum number of columns in which they can march.

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get32=8×4+0

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get32=8×4+0Since the remainder is zero, we cannot proceed further.

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get32=8×4+0Since the remainder is zero, we cannot proceed further.Step 4: Hence the divisor at the last process is 8

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get32=8×4+0Since the remainder is zero, we cannot proceed further.Step 4: Hence the divisor at the last process is 8So, the H.C.F. of 616 and 32 is 8.

HCF (616,32) is the maximum number of columns in which they can march.Step 1: First find which integer is larger.616>32Step 2: Then apply the Euclid's division algorithm to 616 and 32 to obtain616=32×19+8Repeat the above step until you will get remainder as zero.Step 3: Now consider the divisor 32 and the remainder 8, and apply the division lemma to get32=8×4+0Since the remainder is zero, we cannot proceed further.Step 4: Hence the divisor at the last process is 8So, the H.C.F. of 616 and 32 is 8.Therefore, 8 is the maximum number of columns in which they can march.

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