Question

An army contingent of 616 members is to march behind an army band of 32 members in
a parade. The two groups are to march in the same number of columns What is the
maximum number of columns in which they can march?​

Answer 1

Answer:

in this situation we need to find HCF of 32 and 616

Explanation:

32= 2⁵

616= 2³*7*11

HCF (32,616)= 2³= 8

The maximum no. of coloumns in which they can March is 8

Answer 2

$\huge \fbox \red{Solution:}$

It is given that an army contingent of 616 members is to march behind an army band of 32

members in a parade. Also, the two groups are to march in the same number of columns.

Thus, we need to find the maximum number of columns in which they can march.

This is done by simply finding the HCF of the given two numbers.

Therefore, the maximum number of columns = H.C.F of 616 and 32.

$\fbox \blue{By applying Euclid’s division lemma}$

616 = 32 x 19 + 8

32 = 8 x 4 + 0.

So, H.C.F. = 8

$\fbox \blue{∴ The maximum number of columns in which they can march is 8.}$

$\bold\orange{Thanks}$