Math, asked by aru2583, 11 months ago

an army contingent of 616 membeus
is to march o bebind an
army band of 32 membens in a
parade. the two grors are
to march in the Same number
of columns what is the marimum
numbeu of columns in which
thercanmauch ?

Answers

Answered by VirajSpidey
2

Answer:

8

Step-by-step explanation:

HCF of 616 and 32 is 8

616 = 2×2×2×11×7

32=2×2×2×2×2

HCF = 2×2×2

=8

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