Question

an army contingent of 616 memebers is to marxh behind an army band of 32 memebers in a parade. The two groups are to march in the same number of columns. what is the .maximum number of columns in which they can march​

Answer 1

Hey Mate❤️...

We have to HCF,

616 = 32×19+8

32=4+0

The HCF is 8.

they can march 8 columns in each.

Answer 2

HeYa❤️...

Answer:

According to question,

We have to find HCF,

$616 = 32 \times 19 + 8 \\ 32 = 4 + 0$

We get HCF = 8.

Hence, 8 number of columns they can march.

I hOpe It HeLpS Ya!

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