Question

An Army contingent of 678 soldiers is to March behind an army band of 36 members in a Republic Day parade the two groups are to March in the same number of columns then what is the maximum number of columns they can March?

Answer 1

Solution:- An Army contingent of 678 soldiers is to March behind an army band of 36 members in a Republic Day parade the two groups are to March in the same number of columns.

Maximum number of columns is the HCF of 678 and 36.

Now,

678 = 2 × 3 × 113

and 36 = 2 × 2 × 2 × 3 × 3

=> HCF(678,36) = 2 × 3 = 6.

So, maximum number of columns is 6.

[Answer:-6 columns]

Answer 2

total soldiers = 678

members in army band = 36

let us find the HCF of 678 and 36 to find  the maximum number of columns in which they can March

678 > 36

678 = 36 x 18 + 30

 36 = 30 x 1 + 6

 30 = 6 x 5 + 0

here the remainder is zero

so, HCF = 6

therefore, in 6  number of columns they can March

hope it helps....