an army contingent of616 members to march behind an army band of 32 members in a parade . the two groups are to march in the same no. of columns. wt is the maximum no. of columns in which they can March?
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To find the maximum no. of columns in which they can March , we have to find the H.C.F of 616 and 32
616 = 2×2×2×7×11
32=2×2×2×2×2
HCF = 2×2×2 = 8
Therefore , maximum no. of columns in which they can March is 8
616 = 2×2×2×7×11
32=2×2×2×2×2
HCF = 2×2×2 = 8
Therefore , maximum no. of columns in which they can March is 8
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