an army group of 308 members is to march behind an army band of 24 members in a parade. the two groups are to march in the same number of columns what is the maximum number of columns in which they can march ?
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Answered by
25
hey! here is your answer ☺
We have to find the H.C.F of the two numbers to find the maximum number of columns in which they can march. So,
308 =2×2×7×11
24. = 2×2×2×3
HCF= 2×2
=4
There fore the HCF (308,24) = 4
The maximum number of columns are 4 in which they can march.
hope this helps!
We have to find the H.C.F of the two numbers to find the maximum number of columns in which they can march. So,
308 =2×2×7×11
24. = 2×2×2×3
HCF= 2×2
=4
There fore the HCF (308,24) = 4
The maximum number of columns are 4 in which they can march.
hope this helps!
Answered by
18
Here is your answer.
Hope it helps.
Hope it helps.
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Koreanlover:
Thankx.
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