Math, asked by Gurmehak2190, 8 months ago

An army lost 10% of its men in war, 10% of the remaining died due to disease and 10% of the rest were declared disabled. Thus the strength of the army was reduced to 7,29,000 active men. The original strength of the army was

A) 1500000 B) 1000000 C) 1200000 D) 1100000

Answers

Answered by nigamsoni014
1

Answer: original army be x

x*90/100 *90/100 *90/100 = 729000

x = 100/90 *100/90 *100/90 *729000

x = 1000000

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Answered by sanvi7031
6

  • The original strength of the Army was 10,00,000.

Step-by-step explanation:

Suppose the Army has 100 men

Then number of the lost men = 10% of 100

 =  \frac{100}{100}  \times 10 \\  = 10

Remainder = 90

Men died due to disease = 10% of 90

 =  \frac{90}{100}  \times 10 \\  = 9

Now Remainder = 90 - 9 = 81

Men declared disabled = 10% of 81

 =  \frac{81}{100}  \times 10 \\ =  8.1

Remainder = 81 - 8.1 = 72.9

If the reduced strength is 72.9,original strength = 100

If the reduced strength is 729000,original strength

 =  \frac{100}{72.9}  \times 729000 = 1000000

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