Question

An army pilot is flying an aeroplane at an altitude of 1800m observes some suspicious activity of 2 ships which are sailing towards it in the same directions and immediately report it to the navy chief.the angles of depression of the ships are observed from the aeroplane are 60 degree and 30 degree respectively. Find the distance between two ships.

Answer 1

Answer:

4360m precisely or 5400-1800√3 m

Step-by-step explanation:

here, A is ship observed at an angle of depression of 30° and B at 60°

Now DC is the altitude of plane i.e 1800m

in triangle ADC

tan30°=DC/AC

1/√3=1800/AC

AC=1800√3m

now in triangle BCD

tan60°= DC/BC

√3=1800/BC

BC=1800/√3m

therefore distance between ships is

AC-BC =AB

1800√3-1800/√3=AB

AB=4360m

hope it satisfies

Answer 2

Step-by-step explanation:

above is the detailed answer for ur question