Question

An army vehicle of mass 1000 kg is moving with a velocity of 10 ms and is acted upon by a forward force of 1000 N due to the engine and a retarding force of
500 N due to friction What will be its velocity after 10 s?​

Answer 1

Answer:

Explanation:

In this case, we’ll see the net force acting on the vehicle.

Net force = 1000N — 500N = 500N.

Now, just recall a formula,

V = u + at. Here, V is the final velocity, u is the initial velocity, a is the acceleration and t is time taken.

So, we've

Time = 10 second

Initial velocity = 10 m/s.

Acceleration = Force / mass = 500/1000 = 0.5 m/s^2.

Therefore,

V = 10 + 0.5*10 => 10 + 5 =15m/s.

Therefore, the speed after 10 seconds will be 15 m/s or 54 km/h.

Hope you got your answer. Thanks…