Question

An arrangement of three parallel straight wires
placed perpendicular to plane of paper carrying
same current | along the same direction is shown
in Fig. Magnitude of force per unit length on the
middle wire 'B' is given by
[NEET-2017]
90°
ΑΟ​

Answer 1

Answer:

Force per unit length of two wires is given at middle wire is given as

$F_{net} = \frac{\sqrt2 \mu_o I^2}{2\pi d}$

Explanation:

As we know that the magnetic force per unit length between any two wires is given as

$F = \frac{\mu_o I^2}{2\pi d}$

since current flowing in same direction in all wires so they both will attract the middle wire

Now since the middle wire is at perpendicular position with respect to other two wires

So we will have

$F_{net} = \sqrt{F^2 + F^2}$

$F_{net} = \sqrt2 F$

$F_{net} = \frac{\sqrt2 \mu_o I^2}{2\pi d}$

#Learn

Topic : Magnetic force

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Answer 2

Explanation:

hope this will help you ☺️