Question

An arrow 2.5cm high is placed at a distance of 25 cm from a diverging mirror of focal length 20 cm. find the nature, position and size of the image formed
(11.1, 1.11cm).​

Answer 1

Answer:

As it is a diverging mirror, the nature will surely be diminished, virtual and erect.

Distance of arrow from mirror(u) =-25cm(front of mirror)

Let distance of image from mirror be v

focal length(f)=20cm(behind the mirror)

As we know,

1/v+1/u=1/f

=>1/v=1/20+1/25

=>1/v=(5+4)/100

=>1/v=9/100

=>v=100/9cm(behind the mirror)

Therefore the position f the image is 11 1/9cm behind the mirror.

Let the size of the image be I.

Size of object=2.5cm

As we know,

I/O=v/u

=>I/2.5=100/(9*25)

=>I=4/9 * 2.5

=>I=10/9cm

Therefore, the size of image is 10/9cm.

Explanation:

Yes so the answer matches!

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