Question

An arrow 2.5cm high is placed at a distance of 25cm from a diverging mirror of focal length 20 cm.Find the nature,position and sige of the image formed.

Answer 1

Answer:

h1 = +2.5cm

u = -25cm

f = +20cm

1/f = 1/v + 1/u

1/20 = 1/v -1/25

1/v = 1/20 + 1/25

1/v = 9/100

v = +11.11 cm

m = h2/h1 = -v/u

h2/2.5 = -11.11/-25

h2 = +1.11 cm

Hence the image will be formed at 11.11 cm behind the mirror, which will be virtual, erect and of 1.11cm size.