Question

An arrow is aimed horizontally, directly at the center of a target 20 m away. The arrow hits 0.050 m below the center of the target. Neglecting air resistance, what was the initial speed of the arrow?

Answer 1

Answer:

For a horizontal projectile (viy = 0 m/s) to fall 0.05 m takes (using 0.05 m = ½ gt2) 0.1 seconds. To travel 20m in this time requires a speed of d/t = (20m)/(0.1s)Read more on Sarthaks.com - https://www.sarthaks.com/369391/an-arrow-is-aimed-horizontally-directly-at-the-center-of-a-target-20-m-away)

Explanation:

Answer 2

Given : An arrow is aimed horizontally, directly at the center of a target 20 m away.

The arrow hits 0.050 m below the center of the target.

Neglecting air resistance,

To Find : the initial speed of the arrow

Solution:

Initial  initial speed of the arrow   =  Ux  m/s   ( horizontally )

Vertically  Uy = 0 m/s

Horizontal Distance covered = 20 m

20 =  Ux * t

Time taken t  =  20/Ux   secs

Vertical distance covered  = 0.050 m

S =Uyt  + (1/2)at²

=> 0.050  = 0  + (1/2) g( 20/Ux)²

=>  1/20  = (1/2) g (400/Ux²)

=> Ux² = 10 * 400 * g

g = 10 m/s²

=> Ux² = 10 * 400 * 10

=> Ux = 200  

Hence  initial speed of the arrow = 200 m/s

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