An arrow is launched straight up with a velocity of 15.0 m/s. How long before the arrow returned to the ground?
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Answer:
v=u-at
v=0
u=15
a=9.8
up time t = 15/9.8=1.53 sec
up time = down time = 1.53 sec
total time = 3.06 sec approx
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Explanation:
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