An arrow is shot vertically upward from a platform 35ft high at a rate of 173ft/sec. When will the arrow hit the ground? Use the formula: h=−16t2+v0t+h0.
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Answer:
ʜ(ᴛ) = -16ᴛ2 + 186ᴛ + 43
ᴀᴛ ᴛʜᴇ ɢʀᴏᴜɴᴅ ʜ = 0
ʜᴇɴᴄᴇ; -16ᴛ2 + 186ᴛ + 43 = 0
sᴏʟᴠɪɴɢ ᴛʜɪs ǫᴜᴀᴅʀᴀᴛɪᴄ ᴇǫᴜᴀᴛɪᴏɴ ᴜsɪɴɢ ᴛʜᴇ ǫᴜᴀᴅʀᴀᴛɪᴄ ғᴏʀᴍᴜʟᴀ ; ᴀ = -16, ʙ = 186, ᴄ = 43 ; x = (-ʙ +-(ʙ2 - 4ᴀᴄ)1/2)/2ᴀ
ɢɪᴠᴇs ᴛ = 11.8 sᴇᴄᴏɴᴅs ᴛᴏ ᴛʜᴇ ɴᴇᴀʀᴇsᴛ ᴛᴇɴᴛʜ (ɴᴏᴛᴇ ᴛʜᴀᴛ ᴛʜᴇ ɴᴇɢᴀᴛɪᴠᴇ ʀᴏᴏᴛ ʜᴀs ɴᴏ ᴘʀᴀᴄᴛɪᴄᴀʟ sɪɢɴɪғɪᴄᴀɴᴄᴇ)
l hope it will help u ☺️✌️☺️
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