An arrow is shot vertically upwards into the air with an initial velocity of 20ms. How high does the arrow go?
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Hope this helps you
There are also formula to find maximum range/horizontal displacement and time taken
There are also formula to find maximum range/horizontal displacement and time taken
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Aman55555:
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Answered by
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Hey!
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u= 20 m/s
v= 0 [At highest point, the velocity becomes 0]
a= - 10 m/s^2 [ '-' is used because object is thrown against the gravity ]
s=?
Using 3rd equation of motion, we can find out the Answer.
v^2 - u^2 = 2as
0 - (20)^2= 2×-10×s
0 - 400 = -20s
-400 = -20 s
400 = 20 s
s = 400/20
s= 20 m
NOTE-:
u= initial velocity
v= final velocity
a= acceleration
s= distance travelled
_________________________
Hope it helps...!!!
_________________________
u= 20 m/s
v= 0 [At highest point, the velocity becomes 0]
a= - 10 m/s^2 [ '-' is used because object is thrown against the gravity ]
s=?
Using 3rd equation of motion, we can find out the Answer.
v^2 - u^2 = 2as
0 - (20)^2= 2×-10×s
0 - 400 = -20s
-400 = -20 s
400 = 20 s
s = 400/20
s= 20 m
NOTE-:
u= initial velocity
v= final velocity
a= acceleration
s= distance travelled
_________________________
Hope it helps...!!!
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