Question

An arrow leaves a bow with a speed of 42 m/s. Its velocity is reduced to 34 m/s by the time it hits its target. If it was in the air for 2.4 seconds the distance the arrow traveled was ? m.

Answer 1

Hope it's helpful to u.

Answer 2

Answer:

The distance traveled by the arrow is s=130.472 m

Explanation:

The initial speed of the arrow is u=42 m/s

The final speed of the arrow is v=34 m/s

The time arrow traveled in the air is t=2.4 s

The acceleration of the arrow is

$a=\dfrac{v-u}{t}\\a=\dfrac{34-42}{2.4}\\a=\dfrac{-8}{2.4}\\a=-3.33\ m/s^2$

From the equation of the motion

$s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{34^2-42^2}{2\times -3.33}\\\\s=130.472\ m$