An arrow leaves a bow with a speed of 42 m/s. Its velocity is reduced to 34 m/s by the time it hits its target. How much distance did the arrow travel over if it were in the air for 2.4 seconds?
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according to me
the distance = v×t (v1=42m/s ; t= 2.4s ;v2=8m/s
S=42×2.4
S =100.8 m
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