An arrow of 2.5 cm high is placed at a distance of 25 cm from a diverging mirror of focal lenght of 20 cm ? find the nature, position and size of the image formed ?
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Position of the image :
1/u + 1/v = 1/f
1/20 - 1/25 = 1/100
Image position is: 100 cm
Since the image distance is positive the image is real.
From the image and object distance we can get the magnification.
Magnification is :
100 / 25 = 4
4 = hi / 2.5
Hi = 2.5 × 4 = 10cm
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Answer:
Position of the image :
1/u + 1/v = 1/f
1/20 - 1/25 = 1/100
Image position is: 100 cm
Since the image distance is positive the image is real.
From the image and object distance we can get the magnification.
Magnification is :
100 / 25 = 4
4 = hi / 2.5
Hi = 2.5 × 4 = 10cm
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Explanation:
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