Question

An arrow shot vertically upward loses its initial speed by 60% in 3 sec . The maximum hieght reached by the the arrow is ?

Solve with full steps !

Answer 1

Heya.....!!

Let the initial speed be u ,, so after 3 sec it speed will be 2/5u

so from first equation of motion
v = u + at

2/5u = u - 9.8×3

u = 9.8×3×5/3 = 49m/s
u = 49m/s

Now third equation of motion

v^2=u^2+2as

at maximum height , V = 0

, So H = u^2/2g

H = 49×49/2×9.8

H = 122.5 m



HOPE IT HELPS U

Answer 2

u = 49m/s



H = 49×49/2×9.8

H = 122.5 m