Math, asked by brainylizard, 11 months ago

an article is bought for 620 is sold for 780. second article is bought for 575 is sold for 437 and the third article is bought for 805 is sold for 883. find the profit or the loss as percent on the whole​

Answers

Answered by sahasraramadugu2005
3

C. P for the 1st article = 620 rupees

S. P for the first article = 780 rupees

C. P<S.P

thus, profit

P=S.P-C. P

P=780-620

P=160 rupees

C. P of the second article = 575 rupees

S. P of the second article = 437 rupees

C. P>S.P

thus, loss

L=C.P-S. P

L=575-437

L=138 rupees

C. P of the third article = 805 rupees

S. P of the third article = 883 rupees

C. P<S.P

thus, profit

P=S.P-C. P

P=883-805

P=78 rupees

total C. P of the all three articles = 620+575+805

=2000 rupees

total S.P of all three article = 2100 rupees

hence, C. P<S.P

thus, Profit

P=S.P-C. P

P=2100-2000

P=100 rupees

Profit%=profit/C.P×100

P%=100/2000×100

P%=5%

Answered by adwaitsharma6634
0

Answer:

The Answer would be - 5%

Step-by-step explanation:

Add all the C.P

Then Add all the S.P

The Subtract the S.P from C.P

Then use the formula as Profit/C.P Multiplied by 100.

Then Profit Multiplied by 100.

Then Profit Multiplied by 100/C.P

Then Cut the Zero

Then you would get 10/2

Then read the table of Ten till 10 comes.

And the ANSWER = 5%

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