Math, asked by rockaman917, 4 days ago

An article is marked 36% above its cost price. A discount of 10% is offered on the marked price.
Later on, the article was sold by giving another discount of Rs.12.60. If there is a profit of 15.4%,
the marked price (in Rs.) of the article is:

Answers

Answered by akichanbaby650
10

Step-by-step explanation:

let, the marked price is Rs. x

CP of the article Rs. 100x/136 (according to question)

---->After 1st discount SP of the article is Rs. 90x/100

---->After 2nd discount SP of the article is

Rs. (90x/100-12.60)

Profit = SP-CP=Rs. (90x/100-12.60-100x/136)

= Rs. (3060x-42840-2500x)/3400

= Rs. (560x-42840)/3400

According to problem,

(560x-42840)/3400=100x/136 × 154/1000

=>(560x-42840)/3400= 154x/1360

=> 136(560x-42840)=340×154x

=> 560x-42840 = 52360x/136 = 385x

=> 560x-385x = 42840

=> 175x=42840

=> x=42840/175=244.8

Hence, Marked Price of the article is Rs. 244.8

Answered by anjumanyasmin
0

Given:

let, the marked price is Rs. x

CP of the article Rs. 100x/136 (according to question)

---->After 1st discount SP of the article is Rs. 90x/100  

---->After 2nd discount SP of the article is  

Rs. (90x/100-12.60)

Profit = SP-CP=Rs. (90x/100-12.60-100x/136)

= Rs. (3060x-42840-2500x)/3400  

= Rs. (560x-42840)/3400

According to problem,  

(560x-42840)/3400=100x/136 × 154/1000

=>(560x-42840)/3400= 154x/1360  

=> 136(560x-42840)=340×154x  

=> 560x-42840 = 52360x/136 = 385x  

=> 560x-385x = 42840

Hence, Marked Price of the article is Rs. 244.8

=> 175x=42840  

=> x=42840/175=244.8

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