Math, asked by ahmedrijwan455, 4 months ago

An article is sold at a certain price. If it is sold at 33 % of this price, there is a loss of 33 %. . What is the percentage profit when it is sold at 60% of the original selling price?

Answers

Answered by sarivuselvi
0

Answer:

hi friend!!

Step-by-step explanation:

Let the CP of the article be 3x unit.

SP of the article = 3 × (2/3) = 2 unit

Original price of the article = 6 × (60/100) = 3.6 unit

Profit percentage = [(3.6 - 3)/3] × 100 = 20%

Detailed solution:

As 33.33% fraction value is 1/3 so, let's take the value of SP which is easily divisible:Let SP = 300 on which it is sold

It is sold at 1/3 of this price

∴ SP = 100 and still has loss of 33.33%

So after 66.66% loss, SP = Rs. 100

Which means CP = Rs. 150 (∵ 66.66% of 150 = 100)

Now SP = 300

It is sold at 60% of SP which is our MP = 60% of 300 = Rs. 180

So profit percentage = [(180 - 150)/150] × 100 = 20%

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