Question

An article passing through two hands is solid at a profit of 38% at the original cost price. If the dealer makes a profit of 20%, then the profit per cent made by the second is ?​ Don't spam !​

Answer 1

Answer:

Let original price was Rs. 100.  

With 38% profit the selling price would be

=100+38% of 100=100+  

100

38

​  

×100= Rs. 138

First dealer makes a profit of 20% , then he must have sold it at,

=100+20% of 100=100+  

100

20

​  

×100= Rs. 120

Now, profit for second dealer  =138−120= Rs. 18

% profit =  

100

18

​  

×120=15 %.

Step-by-step explanation:

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Answer 2

Answer:

$\huge\underline\bold {Answer:}$

Let the initial cost price of the article be 100 rupees.

Profit = 20%

S.P. of the 1st dealer

$= \frac{100 \times 120 }{100} = 120 \: rupees$

Let the second profit % = x. Then,

S.P. of the 2nd dealer

$= \frac{120 \times (100 + x)}{100}$

Final S.P. of the article after passing through two hands at a profit = 38%

$= \frac{100 \times (100 + 38}{100} = 138$

Given,

$\frac{120 \times (100 + 38)}{100} = 138$

$= > 12000 + 120x = 13800$

$= > 120x = 1800 \\ = > x = 15\%$

So, if the dealer makes a profit of 20%, then the profit per cent made by the second is 15%.