Physics, asked by radhikaradhika24781, 2 months ago

An artificial satellite is going around the earth close to its surface . what will be orbital velocity of the satellite? Given g = 9.8ms^-2 R = 6.4 × 10 ^6 m​

Answers

Answered by nirman95
11

Given:

An artificial satellite is going around the earth close to its surface .

To find:

Orbital velocity ?

Calculation:

The general expression for ORBITAL VELOCITY is as follows:

 \rm \: v =  \sqrt{ \dfrac{GM}{R} }

  • 'G' is Gravitational Constant and 'M' is mass of earth.

 \rm \: v =  \sqrt{ \dfrac{GM}{{R}^{2} } \times R }

  • GM/R² can be written as 'g' or gravitational acceleration.

 \rm \implies \: v =  \sqrt{ g \times R }

 \rm \implies \: v =  \sqrt{ 9.8 \times 6.4 \times  {10}^{6}  }

 \rm \implies \: v =  \sqrt{62.72 \times  {10}^{6}  }

 \rm \implies \: v = 7.91 \times  {10}^{3}  \: m {s}^{ - 1}

So, orbital velocity is 7.91 × 10³ m/s

Answered by kimtaehyung21
1

Answer:

see the attached for answer

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