Question

An artificial satellite is going around the earth close to its surface . what will be orbital velocity of the satellite? Given g = 9.8ms^-2 R = 6.4 × 10 ^6 m​

Answer 1

Given:

An artificial satellite is going around the earth close to its surface .

To find:

Orbital velocity ?

Calculation:

The general expression for ORBITAL VELOCITY is as follows:

$\rm \: v = \sqrt{ \dfrac{GM}{R} }$

• 'G' is Gravitational Constant and 'M' is mass of earth.

$\rm \: v = \sqrt{ \dfrac{GM}{{R}^{2} } \times R }$

• GM/R² can be written as 'g' or gravitational acceleration.

$\rm \implies \: v = \sqrt{ g \times R }$

$\rm \implies \: v = \sqrt{ 9.8 \times 6.4 \times {10}^{6} }$

$\rm \implies \: v = \sqrt{62.72 \times {10}^{6} }$

$\rm \implies \: v = 7.91 \times {10}^{3} \: m {s}^{ - 1}$

So, orbital velocity is 7.91 × 10³ m/s

Answer 2

Answer:

see the attached for answer