Physics, asked by kainthrajan896, 1 day ago

An artificial satellite is going around the earth close to its surface.what will be orbital velocity of that satellite? Given g=9.8ms–², R=6.4×10⁶m​

Answers

Answered by melasweertheart
2

Explanation:

Answer : C

Answer : CSolution : Here `R=6400 km =6.4xx10^(6)m`, <br> `g=9.8 ms^(-2)` <br> Orbital velocity near the earth's surface is `v_(0)=sqrt(gR)=sqrt(9.8xx6.4xx10^(6))=7290 ms^(-1)` <br> Time period, <br> `T=(2piR)/(v_(0))=(2xx22xx6.4xx10^(6))/(7xx7290)=5079s` <br> `=1.411 h`

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