an artificial satellite is moving in a circular orbit of radius 700 km. calculate its speed if it takes 1 hour to revolve around the earth
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Answered by
1
Answer:
4398 km/hr
Explanation:
Time = 1 hour
the distance travelled within the time = 2πr = 2×π×700 km = 4398.2297 km
speed = distance / time = 4398.2297/1 = 4398.23 km/hr
Answered by
0
Explanation:
700km = 700*1000m = 700000m
1 hour = 60*60 second = 3600 second
distance covered by satellite = 2*pi*r
=2*22/7*700000
=2*22*100000
=4400000m
speed = distance/time
=4400000/3600
=44000/36
=1222.22 m/sec
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