Question

An artificial satellite is moving in a circular orbit of radius
42250 km. Calculate its speed if it takes 24 hours to revolve​

Answer 1

$\huge\dagger\sf\underline\red{Solution :-}$

We have,

$\sf{ Radius (r) = 42250\:km} \\ \\ \sf{ Time (t) = 24\:h} \\ \\ {\sf{ Pi(π) = \dfrac{22}{7} }}$

$\sf\underline\red{To\:Find:-} \\ \\ \: \: \: \: \: \bullet\sf{ Speed(v) = ?}$

$\sf\underline\red{ Formula\:used:} \\ \\ \\ \huge\star{\boxed{\sf{ v = \dfrac{2πr}{t} }}}$

Now,

Putting these values in the above Formula:

We get,

$\blue{\sf{ Speed(v) = \dfrac{ 2 \times 22 \times 42250}{7 \times 24} }} \\ \\ \implies\sf{ v = 11065.4\:Km\:h^{-1} }$

We can convert this speed from Kilometres per hour to kilometres per second by dividing it by the number of seconds in 1h ,

Thus,

${\sf{ v = \dfrac{11065.4}{60 \times 60} km\: s^{-1} }} \\ \\ {\sf{ v = 3.07 \: m\: s^{-1} }}$

Answer 2

3.07 is velocity yeh I find