Question

An artificial satellite is moving in a circular orbit of radius 42250 km. calculate its speed if it takes 24 hours to revolve around the earth?​

Answer 1

Distance covered by the satellite in 24 hours

$s = 2\pi \ r$

$\: \: \: = 2 \times 3.14 \times 42250 = 265464.58 \: km$

Therefore speed of satellite

$v = \frac{distance \: travelled}{time \: taken} = \frac{265464.58}{24 \times 60 \times 60} = 3.07 \: km \: {s}^{ - 1}$

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Answer 2

distance covered by satellite = 42250×1000

time taken by = 24×60×60

speed of satellite = 2πr/t

= 2×22/7×42250×1000/24×60×60

= 3.074 km/hr