Question

an artificial satellite is moving in a cirucular orbit of radius 42250 km . calculate its speed if it takes 24 hours to revolve around the earth

Answer 1

r=42250km
distance covered in 1 revolution,
d=2pie r. (circumference of orbit)
2×22/7×42250=265571.43
time taken in 1 revolution,t= 24h
speed of satellite= distance/ time
265571.43/24=11065.48km/h

Answer 2

Hey there!

Given,

Radius (r) = 42250 km

Time (t) = 24 hours

Distance will equal to perimeter of the orbit

= 2πr

= 2π * 42250

Speed of artificial satelite  

= 2π * 42250/24

= 11059 km/h

Hope It Helps You!