Question

An artificial satellite is moving uniformly in a circular orbit of radius 42250km.find the speed if it takes 24hours to revolve around the earth

Answer 1

Explanation:

Given, radius of the circular orbit = 42250 km

Time taken to revolve around earth = 24 hrs.

Now, first we need to find the circumference of the circle on which the satellite is moving.

And we know the formula to find the circumference which is 2πr. (where r is the radius).

Putting values in the equation,

$2\times \frac{22}{7}\times 42250\\ \\ \implies \frac{1859000}{7}\\ \\ \implies 265571.4286 \\ \\ \therefore \textbf {The distance covered by the satellite is 265571.4286 km.}$

Now, we've to find the speed of the satellite,

$\textsf We\ know\ speed=\frac{distance\ travelled}{time\ taken}\\ \\ \textsf Putting\ values\ in\ the\ equation\\ \\ Speed= \frac{265571.4286}{24}\\ \\ \implies \bf{11065.47 km/h}\\ \\ \\ \textbf{The speed of the satellite is 11065.47 km/h}$

Answer 2

Answer :

The speed of the satellite = 11065.47 km/hr.

Explanation :

Given that :

Time taken by the satellite to complete one revolution around earth = 24 h.

Radius of the circular orbit of along which the satellite is moving = 42250 km.

Distance will equal to perimeter of the orbit  

=>  2πr

=> 2π × 42250 = 265571.43 km.

We know that :

$\bigstar\; \boxed{\sf Speed = \dfrac{Distance\;Travelled}{Time\;Taken}}$

Put the given values :

$\sf \longrightarrow \dfrac{265571.43 km}{24hr}\\\\\sf \longrightarrow 11065.47 km/hr.$

Hence,

The speed of the satellite = 11065.47 km/hr.