Question

An artificial satellite is moving uniformly in a circular orbit of radius 42250 km. Find it's speed if it takes 24hrs to revolve around the Earth.​

Answer 1

Answer:

11,055.41 km/hr

Explanation:

Given :

• Radius of the circular orbit = 42,250 km

• Time taken to revolve around the earth = 24 hrs

To find :

• Speed it takes to revolve around the earth

Speed = distance / time

Distance = 2×3.14×r

Distance = 6.28×42,250

Distance = 2,65,330 kilo metres

The Circumference or the distance covered by the satellite is equal to 2,65,330 kilometres

Time taken = 24 hrs

Speed = 265330/24

Speed = 11,055.41 km/hr

The speed of the satellite is equal to 11,055.41 km/hr

Answer 2

$\huge\tt{Answer:-}$

$\bf{Given:-}$

• Radius $(r)$ of the circular orbit = $42250 \ km$.
• Time it takes $(t)$ = $24 \ h$

$\bf{To \ Find:-}$

Speed $(v)$ it takes to revolve around the particle. (Earth)

________________...

We know,

$\boxed{\tt{v = \frac{2 \pi r}{t}}}$

where,

• v = Speed
• 2πr = Distance (of Circular Orbit = Perimeter of the Circ.)
• t = Time taken.

________________...

Putting the values,

$v = \frac{2 \times \pi \times 42250 \ km}{24 \ h}$

$\implies v = \frac{\cancel{2} \times \pi \times 42250 \ km}{\cancel{24} \ h}$

$\implies v = \frac{42250 \pi \ km}{12 \ h}$

$\implies v ≈ 3521 \pi \ km \ {h}^{-1}$

$\implies v ≈ 3521 \times \frac{22}{7} \ km \ {h}^{-1}$

$\implies v ≈ 11,066 \ km \ {h}^{-1}$ $...(Ans.)$