Question

an artificial satellite is orbiting at 500 kilometre above the Earth's surface take the radius of earth as 6.5 into 10 to the power 6 metre find the acceleration due to gravity at any point along the satellite path

Answer 1

Hello Dear,

◆ Answer -

g' = 8.45 m/s²

◆ Explaination -

# Given -

h = 500 km = 5×10^5 m

R = 6.5×10^6 m

# Solution -

Acceleration due to gravity at height h is calculated by formula -

g' = gR² / (R+h)²

g' = 9.8 × (6.5×10^6)² / (6.5×10^6 + 5×10^5)²

g' = 8.45 m/s²

Hence, acceleration due to gravity at height of 500 km is 8.45 m/s².

Best luck dear...

Answer 2

Answer:

hey mate here is the answer

g' = 8.45 m/s²

◆ Explaination -

# Given -

h = 500 km = 5×10^5 m

R = 6.5×10^6 m

# Solution -

Acceleration due to gravity at height h is calculated by formula -

g' = gR² / (R+h)²

g' = 9.8 × (6.5×10^6)² / (6.5×10^6 + 5×10^5)²

g' = 8.45 m/s²

Hence, acceleration due to gravity at height of 500 km is 8.45 m/s².

hope it helps

pls mark as brainliest