an artificial satellite orbits in a circular path. the height of the satellite from the surface of earth is 36000 km. such a satellite is called geo-stationary satellite. when the satellite is exactly vertically upwards the ground station, it sends a signal. how much time will the signal take to reach the ground station. the speed of signal is 3×10^8
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Given:
An artificial satellite orbits in a circular path. The height of the satellite from the surface of earth is 36,000 km.
The speed of signal is 3 x 108 m/s
To find:
How much time will the signal take to reach the ground station.
Solution:
From given, we have,
The distance between the satellite and the ground station is denoted as "S"
The formula is,
S = vt
where, v = speed of signal = 3 × 10⁸ m/s
t = time taken.
substituting the above values in the formula, we get,
36,000 km = 3 × 10⁸ m/s × t
36,000 km = 300000 km/s × t
36 = 300 × t
t = 36/300 = 0.12 s
Therefore, the time taken by the signal to reach the ground station is 0.12 s.
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