An artificial satellite revolves around the earth at a height of 1000 km. The radius of the earth is 6.38×103km6.38×103km. Mass of the earth =6×1024 kg=6×1024 kgg=6.67×10−11nm3kg−2g=6.67×10−11nm3kg−2. Find the orbital speed.
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Explanation:Calculate the orbital velocity and period of revolution of an artificial satellite of earth moving at an altitude 200km. Radius of earth 6400km, Mass of earth 6x1024 kg and G=6.7x10 Nm kg
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