Question

An artificial satellite revolves around the Earth at a distance of 3400 km. Calculate its orbital velocity and period of revolution. Radius of the Earth = 6400 km; g = 9.8 m/s²

Answer 1

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$\mathfrak{\blue{Solution.}}$v = orbital velocity        we know  g = G M / R²
  d  = 3400 + 6400 km = 10000 km

 gravitational force = centripetal force
   G M m / d²  =  m v² / d
        v² = G M / d  = g R² / d
        v = R √(g/d)

   ω = angular velocity =  v / R = √(g/d)
   T = time period = 2π/ ω  = 2 π √(g/d)

 substitute the values to get answers.

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