Physics, asked by tejarorasimran4482, 10 months ago

An artificial satellite revolves around the earth with an orbital velocity of 5.92km/s . calculate height of the satellite from the surface of earth ?

Answers

Answered by wajahatkincsem
12

Answer:

Radius = R = 1.137 x 10⁴ Km

Explanation:

R= GM/v²

Where G= Gravitational constant= 6.673 x 10⁻¹¹ N m² / Kg²

           M = Mass of Earth = 5.972 x 10²⁴ Kg

           v = Velocity of satellite = 5920 m/s

R = 6.673 x 10⁻¹¹. 5.972 x 10²⁴ / ( 5920)²

  = 3.985 x 10¹⁴ / 3.504 x 10⁷

  = 1.137 x 10⁷ m

  = 1.137 x 10⁴ Km

Answered by adarshbhardwaj090
0

Answer:

Answer Will be 1.137x10 ^4 lms

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