An artificial satellite revolves round the earth in 2.5hours in a circular orbit .find the height of the satellite above the earth assuming earth as a sphere of radius 6370km
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spacecraft's engine ejects mass at a rate of 30 kg/s with an exhaust velocity
of 3,100 m/s. The pressure at the nozzle exit is 5 kPa and the exit area is
0.7 m2. What is the thrust of the engine in a vacuum?
SOLUTION,
Given: q = 30 kg/s
Ve = 3,100 m/s
Ae = 0.7 m2
Pe = 5 kPa = 5,000 N/m2
Pa = 0
Equation (1.6),
F = q × Ve + (Pe - Pa) × Ae
F = 30 × 3,100 + (5,000 - 0) × 0.7
F = 96,500 N
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