Question

An artillery piece which consistently shoots its shells with the same muzzle speed has
maximum range of R. To hit a target which is R/2 from the gun and on the same level, at what
elevation angle should the gun be pointed-
(A) 30°
(B) 45°
(C) 60° (D) 75°


Plzz someone answer with proper steps and explanation​

Answer 1

Answer:

The angle of projection should be 75 degree

Explanation:

As we know that the formula of range for any arbitrary angle is given as

$R = \frac{v^2 sin2\theta}{g}$

now for maximum range we will have

$R_o = \frac{v^2}{g}$

so we have

$sin(2\theta) = 1$

now in order to strike at half of the maximum range we will have

$\frac{R_o}{2} = \frac{v^2 sin(2\theta)}{g}$

$\frac{v^2}{2g} = \frac{v^2 sin(2\theta)}{g}$

$sin(2\theta) = \frac{1}{2}$

$2\theta = 30^o OR 150^o$

$\theta = 75^o$

#Learn

Topic : Projectile motion

https://brainly.in/question/2248877