Math, asked by calebmdavis9, 3 months ago

An artist needs to enlarge a statue by making each linear dimension 75% greater. If N cm^3 of clay was used to make the original sculpture, how many cubic centimeters of clay are needed to make the larger sculpture?

A: N+(0.75)^3

B: N⋅(0.75)^3

C: N⋅(1.75)^3

D: N⋅1.75

ill give 40 points to correct answer

Answers

Answered by Steph0303
147

Answer:

Given that an artist needs 'n³' amount of clay to design a sculpture. We are required to find the amount of clay needed to make the larger sculpture.

Since it is given that the statue is enlarged by 75%, the amount of clay needed in excess is given as:

⇒ 75% of n³

⇒ (75/100) × n³

⇒ 0.75 ( n³ )

Also, we already have n³ amount of clay to make the small sculpture. Hence the total clay required is given as:

⇒ Total Clay = Original Amount + Excess Amount

⇒ Total Clay = n³ + 0.75 n³

⇒ Total Clay = n³ ( 1 + 0.75 )

⇒ Total Clay = 1.75 n³

Hence the amount of clay required to make the larger sculpture is 1.75 n³.

Answered by BrainlyMan05
47

Answer:

1.75N^3 is your answer

Step-by-step explanation:

Question:

An artist needs to enlarge a statue by making each linear dimension 75% greater. If N cm^3 of clay was used to make the original sculpture, how many cubic centimeters of clay are needed to make the larger sculpture?

Given:

  • Each linear dimension to enlarge the statue is 75% greater
  • N cm^3 of clay was used to make the original sculpture

To find:

  • Number of Cubic centimeters of clay to make larger sculpture

Solution:

In this question, an artist enlarges a statue from the actual statue which is N cm^3

To enlarge it, the linear dimensions should be 75% greater

So, According to the question,

Enlarged statue = 75% of N cm^3

= 75/100 \times N cm^3

= 0.75 N cm^3

To get the number of cubic centimeters of clay, we need to add the cubic centimeters of the original statue and to that of the enlarged statue

= N^3 + 0.75N^3

Take N^3 as common:-

N^3(1+0.75)

N^3 (1.75)

= 1.75N^3

Final answer:

1.75N^3 is your answer

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