Math, asked by jeontania07, 1 day ago

An assembly hall is 45m long, 30 m broad and 16m high, it has 5 doors each measuring 4m by 3.5m and 4 windows 2.5m by 1.6m each. Find the cost of papering its walls at the rate of ₹35 per m²​

Answers

Answered by 5306846saisivakumar
2

Answer:

THE ANSWER IS ₹80990

Step-by-step explanation:

Area of 4 walls of the room = [2(l+b)*h] sq.units

So, Area of the 4 walls of the room which is to be papering is = [2(45+30)*16] m^2

Now the area of the four walls is = 2400 m^2

Now we have to find the area of both the five doors and four windows . So here we as follow,

Area of five doors = (4*3.5)m^2 = 14 cm^2

As there are five doors so we have to multiply 14 with 5 , so = (14*5)m^2 = 70 m^2 is the area of the five doors .

Now, Area of four windows =(2.5*1.6)m^2 = 4m^2 is the area of 1 window. As we are having &

4 windows we would multiply 4 with 4 , so

area of four windows is =(4*4)m^2 = 14m^2

Now, area not to be papered = ( Area of the doors)+(Area of the windows) = (14+70)m^2 = 86 m^2 is the area of both the doors and windows and also the area which not to be papered .

Now area to be papered = ( Area of the 4 walls )-(Area of the doors and windows)

= (2400-86)m^2 = 2314 m^2 come the area to be papered . Now ,

1 m^2 of wall would cost ₹ 35 to get papered ;

2314 m^2 of wall would cost = ₹(2314*35) to get papered. so the cost to paper the walls of the assembly is ₹80990

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