Physics, asked by manishsairama31161, 11 months ago

An asteroid of mass m is approaching earth initially at distance of 10 re with speed vi its hit the earth with speed vf ( re and me are radius and mass of earth)

Answers

Answered by DeviIQueen
1

Explanation:

G = 6.674e-11 m³/kgs²

v = √(2Gm((1/r) – (1/(r+h)))

Instantaneous velocity v of a falling object that has travelled

distance d on a planet with mass m and radius r (used for large fall

distances where g can change significantly)

The time t taken for an object to fall from a height r to a height x,

measured from the centers of the two bodies, is given by:

t = (r^3/2)[ arccos√(x/r) + √((x/r)–(x²/r²)) ] / [√(2μ)]

μ = G(m₁ + m₂)

μ is the sum of the standard gravitational parameters of the two

bodies. This equation should be used whenever there is a significant

difference in the gravitational acceleration during the fall.

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