An asteroid of mass m is approaching earth initially at distance of 10 re with speed vi its hit the earth with speed vf ( re and me are radius and mass of earth)
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Explanation:
G = 6.674e-11 m³/kgs²
v = √(2Gm((1/r) – (1/(r+h)))
Instantaneous velocity v of a falling object that has travelled
distance d on a planet with mass m and radius r (used for large fall
distances where g can change significantly)
The time t taken for an object to fall from a height r to a height x,
measured from the centers of the two bodies, is given by:
t = (r^3/2)[ arccos√(x/r) + √((x/r)–(x²/r²)) ] / [√(2μ)]
μ = G(m₁ + m₂)
μ is the sum of the standard gravitational parameters of the two
bodies. This equation should be used whenever there is a significant
difference in the gravitational acceleration during the fall.
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