An astronaught in the satellite feels weighlessness because the force exerted by the satellite floor on the astronaut is equal to zero
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Answer:
This problem depends on the principle of conservation of mechanical energy. That means, if an object is moved, the mechanical energy should be constant in every position.
Mechanical energy = Constant
Kinetic Energy + Potential Energy = Constant
(1/2)mv^2 + mgh = Constant
Now we can solve this problem by using above theorem.
As shown in attached diagram we can take 2 positions.
m = mass of the body
h = starting height of the mass reference to the potential energy zero level
u = starting velocity
v = velocity at 2nd position
g = gravitational acceleration
x = falling distance
by using principle of conservation of mechanical energy,
mechanical energy at 1st position = mechanical energy at 2nd position
(1/2)mu^2 + mgh = (1/2)mv^2 + mg(h-x)
0 + mgh = (1/2)mv^2 + mgh - mgx
mgx = (1/2)mv^2
but, lost of potential(gravitational) energy = mgx = U
Therefore U = (1/2)mv^2
mass of the body = m = 2U/(v^2)
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